Oh sorry Algernon! I think I probably didn't answer because I have no idea haha, I have completely forgotten how to do physics! Also I am not updating these blogs on a regular basis so I might not even have read your comments until now.
The penultimate section on this page, titeled flickr physics photo, should be helpful: http://www.physicsclassroom.com/class/refrn/Lesson-2/Snell-s-Law :)
An example might be what would the refractive index of an object be if the angle of incidence is 30 degrees and the angle of refraction is 19 degrees you'd do sin30/sin19= 1.51 therefore the refractive index is 1.51
And if you wanted to work out what the angle of incidence or redaction is and you have the refractive index and one of the 2 already you just rearrange the formula
example please
ReplyDeleteexample please
ReplyDeleteu really love to blank me dont u. what did i do to u
ReplyDeleteOh sorry Algernon! I think I probably didn't answer because I have no idea haha, I have completely forgotten how to do physics! Also I am not updating these blogs on a regular basis so I might not even have read your comments until now.
DeleteThe penultimate section on this page, titeled flickr physics photo, should be helpful:
http://www.physicsclassroom.com/class/refrn/Lesson-2/Snell-s-Law
:)
You accidentally put angle of reflection in the equation, it should be angle of refraction!
ReplyDeleteAn example might be what would the refractive index of an object be if the angle of incidence is 30 degrees and the angle of refraction is 19 degrees you'd do sin30/sin19= 1.51 therefore the refractive index is 1.51
ReplyDeleteAnd if you wanted to work out what the angle of incidence or redaction is and you have the refractive index and one of the 2 already you just rearrange the formula
Delete